5b^2+17b=14

Solution for 5b^2+17b=14 equation:

5b^2+17b=14

We move all terms to the left:

5b^2+17b-(14)=0

a = 5; b = 17; c = -14;
Δ = b2-4ac
Δ = 172-4·5·(-14)
Δ = 569
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{569}}{2*5}=\frac{-17-\sqrt{569}}{10}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{569}}{2*5}=\frac{-17+\sqrt{569}}{10}
$